x^2-5x-14/5(x-7)

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Solution for x^2-5x-14/5(x-7) equation: 


x in (-oo:+oo)

x^2-((14/5)*(x-7))-(5*x) = 0

(-14/5)*(x-7)+x^2-5*x = 0

x^2-14/5*(x-7)-5*x = 0

x^2-14/5*(x-7)-5*x = 0

x^2-14/5*x-5*x+98/5 = 0

x^2-39/5*x+98/5 = 0

x^2-39/5*x+98/5 = 0

x^2-39/5*x+98/5 = 0

DELTA = (-39/5)^2-(1*4*98/5)

DELTA = -439/25

DELTA < 0

1 = 0

1 = 0

x belongs to the empty set

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